document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403529>Question 403529</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 inch more than four times its width. The perimeter is 52 inches. Find the length and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285322 by </B><A HREF=/tutors/aboutme.mpl?userid=Nada><B>Nada(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nada><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Nada><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l > is the length & w > is the width <BR>\n" );
document.write( "Because a perimater of a rectangle is > 2( Width + Length ) <BR>\n" );
document.write( "& w = ( w ) & l = ( 4w+1 ) <BR>\n" );
document.write( "then the equation will be 52 = 2 ( (w) + (4w+1) ) <BR>\n" );
document.write( "52 = 2w+8w+2<BR>\n" );
document.write( "52 = 10w+2<BR>\n" );
document.write( "10w = 52-2 >> w = 50/10 = 2 in<BR>\n" );
document.write( "Then to get the length : <BR>\n" );
document.write( "52 = 2(5+L)<BR>\n" );
document.write( "52 = 10+2L<BR>\n" );
document.write( "2L = 52-10 >> L = 42/2 = 21 <BR>\n" );
document.write( "To check your answer : <BR>\n" );
document.write( "2(5+21) = 52 ( answer is correct)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );