document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403483>Question 403483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lenth of a rectangle is three times the width. If the length was increased by 2 in. and the width 1 in. the new perimeter would be 62 in. what is the length and width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285307 by </B><A HREF=/tutors/aboutme.mpl?userid=Nada><B>Nada(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nada><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Nada><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sorry wrong question.\r<BR>\n" );
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document.write( "I will try to do it myself , and post the answer , it takes me a while because I study Algebra in Arabic so it's bit confusing when reading English.\r<BR>\n" );
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document.write( "I'll try my best !\r<BR>\n" );
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document.write( "Here is the asnwer : \r<BR>\n" );
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document.write( "l > is the length & w > is the width \r<BR>\n" );
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document.write( "Because a perimater of a rectangle is > 2( Width + Length ) \r<BR>\n" );
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document.write( "& w = ( w+1 ) & l = ( 3w+2 ) \r<BR>\n" );
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document.write( "then the equation will be  62 = 2 ( (w+1) + (3w+2) )\r<BR>\n" );
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document.write( "62 = 2w+2+6w+4<BR>\n" );
document.write( "62 = 8w+6<BR>\n" );
document.write( "8w = 62-6 >> w = 56/8 = 7 \r<BR>\n" );
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document.write( "Then to get the length : \r<BR>\n" );
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document.write( "62 = 2(7+L)<BR>\n" );
document.write( "62 = 14+2L<BR>\n" );
document.write( "2L = 62-14 >> L = 48/2 = 24\r<BR>\n" );
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document.write( "To check your answer : \r<BR>\n" );
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document.write( "2(7+24) = 62 ( answer is correct)<BR>\n" );
document.write( "Hope I helped. </SPAN>\n" );
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