document.write( "Question 43526: Can you tell me if I have simplified this equation correctly?\r
\n" ); document.write( "\n" ); document.write( "(9y^2/(x^-8*y^0))^1/2\r
\n" ); document.write( "\n" ); document.write( "I first found that y^0 = 1. So that would drop out of the equation.
\n" ); document.write( "Then I thought that raising to the 1/2 is the same as taking the square root of the equation.
\n" ); document.write( "So I now have the square root of 9y^2 / square root of x^-8.
\n" ); document.write( "The square root of 9y^2 is 3y. So I now have 3y/square root of x^-8.
\n" ); document.write( "I think that a negative exponent is the reciprocal of the positive so I now have 3y * square root of x^8. And x^8 is x^4 * x^4. So if I take the square root of x^4 is x^2. So I ended up with 3y*2x^2. Is that right?
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Algebra.Com's Answer #28530 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let's see...you want to simplify:
\n" ); document.write( "\"%289y%5E2%2F%28x%5E%28-8%29%2Ay%5E0%29%29%5E%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "Your first step is correct:\"y%5E0+=+1\", so now yu have:
\n" ); document.write( "\"%289y%5E2%2Fx%5E-8%29%5E%281%2F2%29\"
\n" ); document.write( "Your second statement is also correct:\"x%5E%281%2F2%29+=+sqrt%28x%29\".
\n" ); document.write( "So now you want to multiply the internal exponents by the external exponent:
\n" ); document.write( "\"%289%5E%281%2F2%29%2A%28y%5E2%29%5E%281%2F2%29%29%2F%28x%5E-8%29%5E%281%2F2%29\" Simplify this. For the numerator:\"9%5E%281%2F2%29+=+sqrt%289%29\" = 3 and \"%28y%5E2%29%5E%281%2F2%29+=+sqrt%28y%5E2%29\" = y
\n" ); document.write( "And for the denominator: \"%28x%5E%28-8%29%29%5E%281%2F2%29+=+x%5E%28-4%29\"
\n" ); document.write( "\"3y%2Fx%5E-4\" Now bring the denominator up and change the sign of the exponent.
\n" ); document.write( "\"3x%5E4y\"
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