document.write( "Question 403450: Last problem I'm stuck on...please help!!\r
\n" );
document.write( "\n" );
document.write( "A motorist, traveling along a level highway at a speed of 60 km/h directly toward a mountain, observes that between 1:00 PM and 1:10 PM, the angle of elevation to the top of the mountain changes from 10 degrees to 70 degrees. Approximate the height of the mountain.\r
\n" );
document.write( "\n" );
document.write( "Thanks!!! \n" );
document.write( "
Algebra.Com's Answer #285286 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A motorist, traveling along a level highway at a speed of 60 km/h directly toward a mountain, observes that between 1:00 PM and 1:10 PM, the angle of elevation to the top of the mountain changes from 10 degrees to 70 degrees. Approximate the height of the mountain. \n" ); document.write( ". \n" ); document.write( "Draw the diagram -- it'll help you \"see\" the solution. \n" ); document.write( ". \n" ); document.write( "distance traveled in 10 minutes = 10 km \n" ); document.write( ". \n" ); document.write( "Let x = height of mountain \n" ); document.write( "and y = distance of car at 1:10 and the point perpendicular to peak \n" ); document.write( ". \n" ); document.write( "tan 10 = x/(10+y) \n" ); document.write( "tan 70 = x/y \n" ); document.write( ". \n" ); document.write( "y = x/tan70 \n" ); document.write( ". \n" ); document.write( "tan 10 = x/(10 + x/tan70) \n" ); document.write( "tan10/tan70 = x/(10tan70 + x) \n" ); document.write( "tan10(10tan70 + x) = xtan70 \n" ); document.write( "10tan10tan70 + xtan10 = xtan70 \n" ); document.write( "10tan10tan70 = xtan70 - xtan10 \n" ); document.write( "10tan10tan70 = x(tan70-tan10) \n" ); document.write( "(10tan10tan70)/(tan70-tan10) = x \n" ); document.write( "1.88 km = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |