document.write( "Question 403450: Last problem I'm stuck on...please help!!\r
\n" ); document.write( "\n" ); document.write( "A motorist, traveling along a level highway at a speed of 60 km/h directly toward a mountain, observes that between 1:00 PM and 1:10 PM, the angle of elevation to the top of the mountain changes from 10 degrees to 70 degrees. Approximate the height of the mountain.\r
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Algebra.Com's Answer #285286 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
A motorist, traveling along a level highway at a speed of 60 km/h directly toward a mountain, observes that between 1:00 PM and 1:10 PM, the angle of elevation to the top of the mountain changes from 10 degrees to 70 degrees. Approximate the height of the mountain.
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\n" ); document.write( "Draw the diagram -- it'll help you \"see\" the solution.
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\n" ); document.write( "distance traveled in 10 minutes = 10 km
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\n" ); document.write( "Let x = height of mountain
\n" ); document.write( "and y = distance of car at 1:10 and the point perpendicular to peak
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\n" ); document.write( "tan 10 = x/(10+y)
\n" ); document.write( "tan 70 = x/y
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\n" ); document.write( "y = x/tan70
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\n" ); document.write( "tan 10 = x/(10 + x/tan70)
\n" ); document.write( "tan10/tan70 = x/(10tan70 + x)
\n" ); document.write( "tan10(10tan70 + x) = xtan70
\n" ); document.write( "10tan10tan70 + xtan10 = xtan70
\n" ); document.write( "10tan10tan70 = xtan70 - xtan10
\n" ); document.write( "10tan10tan70 = x(tan70-tan10)
\n" ); document.write( "(10tan10tan70)/(tan70-tan10) = x
\n" ); document.write( "1.88 km = x\r
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