document.write( "Question 403290: Suppose you have a function y = f(x) such that the domain of f(x) is 1 ≤ x ≤ 6 and the range of f(x) is −3 ≤ y ≤ 5. What is the domain of f(2(x − 3)) \n" ); document.write( "
Algebra.Com's Answer #285250 by jim_thompson5910(35256)\"\" \"About 
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Since the domain is \"1%3C=x%3C=6\", this means that the set of possible input values is {1,2,3,4,5,6}. Say for the sake of argument that we're only dealing with integers (to make things easy for us)\r
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\n" ); document.write( "\n" ); document.write( "Now consider that instead of plugging in 'x', you plug in x-3. So this means that instead of plugging in x=1, you'll plug x-3=1-3=-2 into the function.\r
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\n" ); document.write( "\n" ); document.write( "So this means that the domain of f(x-3) is now\r
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\n" ); document.write( "\n" ); document.write( "\"1-3%3C=x-3%3C=6-3\"\r
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\n" ); document.write( "\n" ); document.write( "which becomes\r
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\n" ); document.write( "\n" ); document.write( "\"-2%3C=x-3%3C=3\"\r
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\n" ); document.write( "\n" ); document.write( "So the domain of f(x-3) is \"-2%3C=x-3%3C=3\"\r
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\n" ); document.write( "\n" ); document.write( "Now we're going to take it a step further. Instead of plugging in x-3, we're going to double it and plug in 2(x-3). So instead of plugging in -2, we're going to plug (-2)(2)=-4 into the function.\r
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\n" ); document.write( "\n" ); document.write( "So this means that the domain becomes\r
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\n" ); document.write( "\n" ); document.write( "\"2%28-2%29%3C=2%28x-3%29%3C=2%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-4%3C=2%28x-3%29%3C=6\"\r
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\n" ); document.write( "\n" ); document.write( "So the domain of f(2(x-3)) is \"-4%3C=2%28x-3%29%3C=6\" given that the domain of f(x) is \"1%3C=x%3C=6\". \r
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\n" ); document.write( "\n" ); document.write( "Basically, the smallest number that the input 2(x-3) can be is -4 and the largest number that 2(x-3) can be is 6
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