document.write( "Question 403350: How do I use the Intercept Form to find the equation of the line with:\r
\n" ); document.write( "\n" ); document.write( "1) X-intercept= -3 and Y-intercept= 2\r
\n" ); document.write( "\n" ); document.write( "2) X-intercept= 5 and Y-intercept= 6\r
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Algebra.Com's Answer #285229 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "1) X-intercept= -3 and Y-intercept= 2\r
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\n" ); document.write( "\n" ); document.write( "X-intercept: -3 means that the point (-3,0) is on the line\r
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\n" ); document.write( "\n" ); document.write( "Y-intercept: 2 means that the point (0,2) is on the line\r
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\n" ); document.write( "\n" ); document.write( "So let's find the equation of the line through the points (-3,0) and (0,2)\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, 0) and (x2, y2) = (0, 2).
\n" ); document.write( " Slope a is .
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"0.666666666666667%2A-3+%2Bb+=+2\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=0-0.666666666666667%2A-3+=+2\".
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\n" ); document.write( " y=(0.666666666666667)x + (2)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "2) X-intercept= 5 and Y-intercept= 6\r
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\n" ); document.write( "\n" ); document.write( "let's find the equation of the line through the points (5,0) and (0,6)\r
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Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 0) and (x2, y2) = (0, 6).
\n" ); document.write( " Slope a is \"a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-0%29%2F%280-5%29+=+-1.2\".
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-1.2%2A5+%2Bb+=+6\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=0--1.2%2A5+=+6\".
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\n" ); document.write( " y=(-1.2)x + (6)
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\n" ); document.write( " Your graph:
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