document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403309>Question 403309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Some children are standing in a circular arrangement. they are evenly spaced and marked in numerical order. the fourth child is standing directly opposite the twelfth child. how many children are in the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285223 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw a picture and you'll see that kids #5 through #11 will be in between #4 and #12 (note: we at least know that there are 12 kids). So there are 11-5+1 = 7 kids that are between #4 and #12\r<BR>\n" );
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document.write( "So because of symmetry, this means that there must be 7 kids in between kid #12 and kid #4 (say the circle starts at kid #4, so it wraps around back to the kid #4). So add 7 to 12 to get 19. Now realize that there are kids #1, #2, and #3 (which are before #4), so we have to subtract 3 from 19 to get 16 (since we've over counted). So there are 16 kids in the circle.  </SPAN>\n" );
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