document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403306>Question 403306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 130 milliliters of a 31% solution but has only 17% and 43% solutions availble. Find how many millimiters of each that should be mixed to get the desired solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285205 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A chemist needs 130 milliliters of a 31% solution but has only 17% and 43% solutions availble. Find how many millimiters of each that should be mixed to get the desired solution.<BR>\n" );
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document.write( "f = amount of 43%<BR>\n" );
document.write( "s = amount of 17%<BR>\n" );
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document.write( "f + s = 130 (total solution)<BR>\n" );
document.write( "0.43f + 0.17s = 130*0.31  (total of what's in the solution)<BR>\n" );
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document.write( "43f + 17s = 4030<BR>\n" );
document.write( "s = 130 - f<BR>\n" );
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document.write( "43f + 17(130-f) = 4030<BR>\n" );
document.write( "26f = 1820<BR>\n" );
document.write( "f = 70 ml<BR>\n" );
document.write( "s = 60 ml<BR>\n" );
document.write( " </SPAN>\n" );
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