document.write( "Question 403268: 2-3x < or equal to x+14 \n" ); document.write( "

Algebra.Com's Answer #285195 by checkley79(3341) $\"\"$ $\"About$

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2-3x <=x+14
\n" ); document.write( "-3x-x>=14-2
\n" ); document.write( "-4x>=12
\n" ); document.write( "x<=12/-4 (note the sogn change when dividing by a negative value).
\n" ); document.write( "x<=-3 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "2-3*-3<=-3+14
\n" ); document.write( "2+9<=11
\n" ); document.write( "11<=11 \n" ); document.write( "

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