document.write( "Question 403241: a farmer keeps hens and rabbits on his form.one day he counted a total of 70 heads and 196 legs. how many more hens than rabbits does he have? \n" ); document.write( "

Algebra.Com's Answer #285157 by Edwin McCravy(20056) $\"\"$ $\"About$

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a farmer keeps hens and rabbits on his form.one day he counted a total of 70 heads and 196 legs. how many more hens than rabbits does he have?
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document.write( "Two methods:\r\n" );
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document.write( "1. Without using algebra:\r\n" );
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document.write( "196 legs is the same as half that number of leg pairs, or 98 leg pairs.  Hens\r\n" );
document.write( "and rabbits both have 1 front leg pair each.  Only rabbits have 1 back leg pair\r\n" );
document.write( "each.  There are 70 heads, so there are 70 animals.  Those 70 animals each have\r\n" );
document.write( "1 pair of front legs. So 70 of the 98 total leg pairs are front leg pairs, and\r\n" );
document.write( "the remaining 28 are back leg pairs, so there are 28 rabbits and \r\n" );
document.write( " 70-28 or 42 hens.\r\n" );
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document.write( "2. With algebra:\r\n" );
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document.write( " h +  r =  70\r\n" );
document.write( "2h + 4r = 196   \r\n" );
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document.write( "Solve that system and get h = 42, r = 28\r\n" );
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document.write( "Edwin

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