document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403257>Question 403257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is 5 more than 3 times another number,the sum of two numbers is 157.find the bigger number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285156 by </B><A HREF=/tutors/aboutme.mpl?userid=rvquartz><B>rvquartz(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rvquartz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rvquartz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285156\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = that \"one number\" described first<BR>\n" );
document.write( "let y = that \"another number\" described second\r<BR>\n" );
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document.write( "from the problem statement we know two things\r<BR>\n" );
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document.write( "(a) x + y = 157<BR>\n" );
document.write( "(b) x = 3y + 5\r<BR>\n" );
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document.write( "use (a) to substitute describe y in terms of x: y = (157 - x)\r<BR>\n" );
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document.write( "use (b) substituting for y: x = 3(157 - x) + 5\r<BR>\n" );
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document.write( "solving for x: x = 471 - 3x + 5\r<BR>\n" );
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document.write( "this is the same as\r<BR>\n" );
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document.write( "4x = 476\r<BR>\n" );
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document.write( "so x = 476/4\r<BR>\n" );
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document.write( "so x = 119\r<BR>\n" );
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document.write( "since y = 157 - x = 157 - 119\r<BR>\n" );
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document.write( "y = 38\r<BR>\n" );
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document.write( "the bigger number is 119 </SPAN>\n" );
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