document.write( "Question 403213: Here is another one I would need help with:
\n" ); document.write( "Kevin was swimming agains the current, it took him 8 min. to swim 200 meters. Swimming back with the current took half as long. What is his average swimming speed and the speed of the current?
\n" ); document.write( "Thank you for your help
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Algebra.Com's Answer #285139 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"k\" = rate of swimming without current
\n" ); document.write( "Let \"c\" = rate of current
\n" ); document.write( "\"k+-+c\" = rate of swimming against current
\n" ); document.write( "\"k+%2B+c\" = rate of swimming with current
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\n" ); document.write( "given:
\n" ); document.write( "(1) \"200+=+%28k+-+c%29%2A8\" meters
\n" ); document.write( "(2) \"200+=+%28k+%2B+c%29%2A4\" meters
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\n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "(1) \"8k+-+8c+=+200\"
\n" ); document.write( "(2) \"4k+%2B+4c+=+200\"
\n" ); document.write( "Multiply both sides of (2) by \"2\"
\n" ); document.write( "and add the equations
\n" ); document.write( "(1) \"8k+-+8c+=+200\"
\n" ); document.write( "(2) \"8k+%2B+8c+=+400\"
\n" ); document.write( "\"16k+=+600\"
\n" ); document.write( "\"k+=+37.5\"
\n" ); document.write( "and, from (2),
\n" ); document.write( "(2) \"k+%2B+c+=+50\"
\n" ); document.write( "\"+c+=+12.5\"
\n" ); document.write( "-----------------
\n" ); document.write( "Always use the definition (ave. speed) = (total distance)/(total time)
\n" ); document.write( "His ave. speed = \"%28200+%2B+200%29%2F%288+%2B+4%29+=+400%2F12\"
\n" ); document.write( "\"400%2F12+=+33.333\" m/min
\n" ); document.write( "The speed of the current is 12.5 m/min
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