document.write( "Question 403073: Hi, can you please help me?\r
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document.write( "I need to factor the following completely:\r
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document.write( "21x^3-18x^2y+24xy^2
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document.write( "Can you please show me how?
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document.write( "thank you! \n" );
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Algebra.Com's Answer #285115 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "When factoring, always start with the Greatest Common Factor (GCF). The GCF here is 3x: \n" ); document.write( " \n" ); document.write( "Always keep factoring until no more factoring can be done. The second factor is a trinomial we should try to factor. It does not fit any of the patterns for factoring. But we can try trinomial factoring. This factoring is \"un-FOIL-ing\" the expression. We are looking to see if some pair of binomials will result in \n" ); document.write( " \n" ); document.write( "where \n" ); document.write( "For \n" ); document.write( "So the possibilities are: \n" ); document.write( "(7x-8y)(x-y) \n" ); document.write( "(7x-y)(x-8y) \n" ); document.write( "(7x-2y)(x-4y) \n" ); document.write( "or \n" ); document.write( "(7x-4y)(x-2y) \n" ); document.write( "All of these will produce the \n" ); document.write( "(7x-8y)(x-y) \n" ); document.write( "Outside: 7x*(-y) = -7xy \n" ); document.write( "Inside: x*(-8y) = -8xy \n" ); document.write( "Together they make -15xy \n" ); document.write( "(7x-y)(x-8y) \n" ); document.write( "Outside: 7x*(-8y) = -56xy \n" ); document.write( "Inside: x*(-y) = -xy \n" ); document.write( "Together they make -57xy \n" ); document.write( "(7x-2y)(x-4y) \n" ); document.write( "Outside: 7x*(-4y) = -28xy \n" ); document.write( "Inside: x*(-2y) = -2xy \n" ); document.write( "Together they make -30xy \n" ); document.write( "(7x-4y)(x-2y) \n" ); document.write( "Outside: 7x*(-2y) = -14xy \n" ); document.write( "Inside: x*(-4y) = -4xy \n" ); document.write( "Together they make -18xy \n" ); document.write( "None of these produced the -6xy we were looking for. So \n" ); document.write( " |