document.write( "Question 403159: equation using substitution method
\n" ); document.write( "y=2/3x-1
\n" ); document.write( "2x+3y=21 \n" ); document.write( "

Algebra.Com's Answer #285114 by mananth(16946) $\"\"$ $\"About$

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y=2/3x-1......1
\n" ); document.write( "2x+3y=21......2 \r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "substitute the value of y in second equation\r
\n" ); document.write( "\n" ); document.write( "2x+3(2x/3-1)=21
\n" ); document.write( "LCD of the parenthesis is 3
\n" ); document.write( " $\"2x%2B%28cross%283%29%29%282x-3%29%2F%28cross%283%29%29+=21\"$ \r
\n" ); document.write( "\n" ); document.write( "2x+2x-3=21\r
\n" ); document.write( "\n" ); document.write( "4x-3=21
\n" ); document.write( "add 3
\n" ); document.write( "4x=24
\n" ); document.write( "/4
\n" ); document.write( "x=6
\n" ); document.write( "...
\n" ); document.write( "plug value of x in (1)\r
\n" ); document.write( "\n" ); document.write( "y=2/3x-1
\n" ); document.write( "y=(2/3)*6 -1
\n" ); document.write( "y=3\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca\r
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