document.write( "Question 403138: Bob has to mix a solution of .67 herbicide and .46 herbicide to form 42 liters of a .55 solution. How much .67 solution does Bob use? \n" ); document.write( "
Algebra.Com's Answer #285104 by rvquartz(19)\"\" \"About 
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based on the problem statement, we can create a mathematical model that says\r
\n" ); document.write( "\n" ); document.write( "x + y = 42 liters\r
\n" ); document.write( "\n" ); document.write( "where
\n" ); document.write( "x = number of liters of the 67% strength solution
\n" ); document.write( "y = number of liters of the 46% strength solution\r
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\n" ); document.write( "\n" ); document.write( "also based on the problem statement, we can create another mathematical model that says\r
\n" ); document.write( "\n" ); document.write( "0.67x + 0.46y = 0.55(42) = 23.1 liters (note: that is the amount of 'pure' 100% acid) \r
\n" ); document.write( "\n" ); document.write( "now we have two separate independent equations and two unknowns\r
\n" ); document.write( "\n" ); document.write( "we can substitute and solve\r
\n" ); document.write( "\n" ); document.write( "y = (42 - x) so\r
\n" ); document.write( "\n" ); document.write( "0.67x + 0.46(42 - x) = 23.1\r
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\n" ); document.write( "\n" ); document.write( "0.67x - 0.46x + 19.32 = 23.1\r
\n" ); document.write( "\n" ); document.write( "0.21x + 19.32 = 23.1\r
\n" ); document.write( "\n" ); document.write( "0.21x = 3.78\r
\n" ); document.write( "\n" ); document.write( "x = 3.78/0.21\r
\n" ); document.write( "\n" ); document.write( "x = 18 liters of the 67% strength solution
\n" ); document.write( "y = 24 liters of the 46% strength solution
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