document.write( "Question 403138: Bob has to mix a solution of .67 herbicide and .46 herbicide to form 42 liters of a .55 solution. How much .67 solution does Bob use? \n" ); document.write( "
Algebra.Com's Answer #285099 by mananth(16946)\"\" \"About 
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Bob has to mix a solution of .67 herbicide and .46 herbicide to form 42 liters of a .55 solution. How much .67 solution does Bob use?\r
\n" ); document.write( "\n" ); document.write( "percent ---------------- quantity
\n" ); document.write( "67.00% ---------------- x
\n" ); document.write( "46.00% ---------------- 42-x
\n" ); document.write( "55.00% ---------------- 42 (Mixture)
\n" ); document.write( "...\r
\n" ); document.write( "\n" ); document.write( "67x+46(42-x)=55*42
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\n" ); document.write( "67x+1932-46x=2310
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\n" ); document.write( "21x=378
\n" ); document.write( "/21
\n" ); document.write( "x=18 liters of .67
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