document.write( "Question 403107: 2lnx=5 \n" ); document.write( "

Algebra.Com's Answer #285068 by jsmallt9(3758) $\"\"$ $\"About$

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First we'll isolate the logarithm by dividin both sides by 2:
\n" ); document.write( "ln(x)=5/2
\n" ); document.write( "or
\n" ); document.write( "ln(x) = 2.5
\n" ); document.write( "Now we'll rewrite the equation in exponential form. In general $\"log%28a%2C+%28p%29%29+=+q\"$ is equivalent to $\"p+=+a%5Eq\"$ . Using this pattern on your equation, keeping in mind that the base of ln is e, we get:
\n" ); document.write( " $\"x+=+e%5E2.5\"$
\n" ); document.write( "This is an exact expression for the solution. If you need a decimal approximation then you'll need your calculator. Just enter e^2.5. If your calculator does not have a button for e, then enter 2.7182818284590451^2.5. \n" ); document.write( "

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