document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403104>Question 403104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One card is selected at random from a deck of a cards.  Determine the probability that the card selected is: A kind and a club.  I am confused on this because it says AND in between king and club.  Do I work these seperately or together since it is the it is both?  I know that there are 4 kings in a deck but only one king of clubs.  Would that be 1/52? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285065 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One card is selected at random from a deck of a cards. Determine the probability that the card selected is: A king and a club. I am confused on this because it says AND in between king and club. Do I work these seperately or together since it is the it is both? I know that there are 4 kings in a deck but only one king of clubs. Would that be 1/52?<BR>\n" );
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document.write( "Yes. P(king AND club) means the card has to satisfy both conditions.<BR>\n" );
document.write( "P(king AND club) = 1/52<BR>\n" );
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document.write( "If the problem had said P(king OR club) the answer would be (4+4)/52<BR>\n" );
document.write( "= 8/52 = 2/13<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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