document.write( "Question 402686: An engine burns 1.4 kg of gasoline per hour and yields 3.5 kW of power.
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document.write( "Calculate the efficiency of the engine when the heating value of gasoline is
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document.write( "43 MJ/kg.
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document.write( "PLEASE HELP \n" );
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Algebra.Com's Answer #285032 by scott8148(6628) You can put this solution on YOUR website! the heat energy in the gasoline is ___ (1.4 kg) * (43 MJ/kg) = 60.2 MJ\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "one Watt is one Joule per second \n" ); document.write( "3600 sec in an hr\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "power generated is ___ (3.5 kW) * (3600 sec) = 12.6 MJ\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "efficiency is ___ (12.6 MJ) / (60.2 MJ) ___ expressed as a percent \n" ); document.write( " |