document.write( "Question 832: how do you graph and solve this quadratic equation\r
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document.write( "-x2 + 3x - 2 = 0 \n" );
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Algebra.Com's Answer #285 by pushpaharan(47)![]() ![]() ![]() You can put this solution on YOUR website! to graph you can either convert into vertex form or factored form. \n" ); document.write( "lets do the vertex form\r \n" ); document.write( "\n" ); document.write( "-x2 + 3x - 2 = 0 \n" ); document.write( "-1(x2 - 3x) - 2 = 0 \n" ); document.write( "-1(x2 - 3x+(3/2)^2-(3/2)^2) - 2 = 0 \n" ); document.write( "-1(x2 - 3x+(3/2)^2-9/4) - 2 = 0 \n" ); document.write( "-1((x-3/2)2 - 9/4) - 2 = 0 \n" ); document.write( "-(x-3/2)2 + 9/4 - 2 = 0 \n" ); document.write( "-(x-3/2)2 - 1/4 = 0 \n" ); document.write( "your vertex = (3/2,-1/4) \n" ); document.write( "axis of symmetry is x=3/2\r \n" ); document.write( "\n" ); document.write( "then draw the parabola.!! \n" ); document.write( "oops it asked to solve too... \n" ); document.write( "therefore its better use factored form \n" ); document.write( "-x2 + 3x - 2 = 0 \n" ); document.write( "-1(x2 - 3x+ 2) = 0 \n" ); document.write( "x2 - 3x+ 2 =0 \n" ); document.write( "(x-1)(x-2)=0\r \n" ); document.write( "\n" ); document.write( "therefore zeros are at x=2 and x=1 \n" ); document.write( "axis of symmetry => x= (2+1)/2 = 3/2\r \n" ); document.write( "\n" ); document.write( "substitute the x=3/2 into the equation \n" ); document.write( "-(3/2)^2+3(3/2)-2 =-1/4 \n" ); document.write( "vertex => (3/2,-1/4)\r \n" ); document.write( "\n" ); document.write( "then draw the parabola. \n" ); document.write( "solution's are x=2 and x=1\r \n" ); document.write( "\n" ); document.write( " |