document.write( "Question 402964: Two cyclists, 72 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "
Algebra.Com's Answer #284997 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Two cyclists, 72 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "----------------------- \n" ); document.write( "Slower cyclist DATA: \n" ); document.write( "Time = 4 hrs ; rate = x mph ; distance = 4x miles \n" ); document.write( "----- \n" ); document.write( "Faster cyclist DATA: \n" ); document.write( "Time = 4 hrs: rate = 2x mph ; distance = 8x miles \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "distance + distance = 72 miles \n" ); document.write( "4x + 8x = 72 miles \n" ); document.write( "8x = 72 \n" ); document.write( "x = 9 mph (rate of slower rider) \n" ); document.write( "--- \n" ); document.write( "2x = 18 mph (rate of faster rider) \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |