document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402708>Question 402708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to determine how much E85 fuel to mix with E10 fuel to arrive at a final mixture of E20 in a 16 gallon gas tank.  I think the equation would be .85X + .1X = .2, but I'm not sure about how you factor in the 16 gallon tank capacity. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284988 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm trying to determine how much E85 fuel to mix with E10 fuel to arrive at a<BR>\n" );
document.write( " final mixture of E20 in a 16 gallon gas tank.<BR>\n" );
document.write( " I think the equation would be .85X + .1X = .2, but I'm not sure about how you<BR>\n" );
document.write( "factor in the 16 gallon tank capacity.<BR>\n" );
document.write( ": <BR>\n" );
document.write( "let x = amt of E85 fuel<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(16-x) = amt of E10<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The equation would be<BR>\n" );
document.write( ".85x + .10(16-x) = .20(16) </SPAN>\n" );
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