document.write( "Question 402843: In how many different ways can a starting lineup of 5 players be selected from a group of 12 basketball players? \n" ); document.write( "

Algebra.Com's Answer #284941 by jim_thompson5910(35256) $\"\"$ $\"About$

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There are 12 P 5 = 12!/(12-5)! = 12!/7! = 12*11*10*9*8*7!/7! = 12*11*10*9*8 = 95040 different ways to arrange a team (assuming that order matters since a center is different from a guard)\r
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