document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402776>Question 402776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> By expressing (1+j) in polar form and using De Moivre's Theorem, show that (1+j)^24 = 2^12. Obtain (1-j)^24.\r<BR>\n" );
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document.write( "Show that (2 sqrt3- 2j)^12 =4^12. Obtain (2 sqrt3+2j)^12\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284893 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By expressing (1+j) in polar form and using De Moivre's Theorem, show that (1+j)^24 = 2^12.<BR>\n" );
document.write( "1+j --> sqrt(2)cis(45º)<BR>\n" );
document.write( "(1+j)^24 = (sqrt(2))^24 cis(45*24) = 2^12 cis (1080)<BR>\n" );
document.write( "= 2^12<BR>\n" );
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document.write( " Obtain (1-j)^24.<BR>\n" );
document.write( "I don't know what that means.  If it means calculate, do it like the one above.<BR>\n" );
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document.write( "Show that (2 sqrt3- 2j)^12 =4^12.<BR>\n" );
document.write( "Similar to the one above.<BR>\n" );
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document.write( " Obtain (2 sqrt3+2j)^12<BR>\n" );
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document.write( "email via the thank you note and I'll check your work.<BR>\n" );
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