document.write( "Question 43485: Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation.\r
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Algebra.Com's Answer #28484 by Nate(3500)\"\" \"About 
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\"9x%5E2+%2B+1+=+6x\"
\n" ); document.write( "\"9x%5E2+-+6x+%2B+1+=+0\"
\n" ); document.write( "Disciminant: \"b%5E2+-+4ac\" where the from: \"ax%5E2+%2B+bx+%2B+c+=+0\"
\n" ); document.write( "a=9 b=-6 c=1
\n" ); document.write( "\"b%5E2+-+4ac\"
\n" ); document.write( "\"%28-6%29%5E2+-+4%289%29%281%29\"
\n" ); document.write( "\"36+-+36\"
\n" ); document.write( "\"0\"
\n" ); document.write( "Since the discriminant is zero, there is only one real root.
\n" ); document.write( "\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+9x%5E2+-+6x+%2B+1%29+\"
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