document.write( "Question 401924: 2x-3y+z=5
\n" ); document.write( "x+3y+8z=22
\n" ); document.write( "3x-y+2z=12
\n" ); document.write( "showsteps also please
\n" ); document.write( "system of equations in three variables
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Algebra.Com's Answer #284839 by sofiyac(983)\"\" \"About 
You can put this solution on YOUR website!
1)****2x-3y+z=5
\n" ); document.write( "2)****x+3y+8z=22
\n" ); document.write( "3)****x-y+2z=12
\n" ); document.write( "******************
\n" ); document.write( "Add equations (eq) 1 and 2.
\n" ); document.write( "3x+9z=27 %%%%%%
\n" ); document.write( "Then multiply eq 3 by 3
\n" ); document.write( "3x-3y+6z=36 and add it to eq 2
\n" ); document.write( "x+3y+8z=22
\n" ); document.write( "_______________
\n" ); document.write( "4x+14z=58 %%%%%%
\n" ); document.write( "Now we will work with equations i marked with %%%%%
\n" ); document.write( "3x+9z=27
\n" ); document.write( "4x+14z=58
\n" ); document.write( "So first one we'll multiply by -4 and second one by 3 and add them
\n" ); document.write( "-12x-36z=-108
\n" ); document.write( "12x+42z=174
\n" ); document.write( "-------------
\n" ); document.write( "6z=66 divide each side by 6 and you get
\n" ); document.write( "z=11 Now lets plug that into the first equation that i maked with %%%%%
\n" ); document.write( "3x+9*11=27
\n" ); document.write( "3x+99=27
\n" ); document.write( "3x=-72
\n" ); document.write( "x=24
\n" ); document.write( "Now lets plug z and x into the third original equation marked 3) and solve for y (i picked this one because it has less coefficients, so less work for us)
\n" ); document.write( "x-y+2z=12
\n" ); document.write( "24-y+2*11=12
\n" ); document.write( "24-y+22=12
\n" ); document.write( "46-y=12
\n" ); document.write( "-y=-34
\n" ); document.write( "y=34
\n" ); document.write( "So the solution is (24,34,11)\r
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