document.write( "Question 402685: Liza is four times as old as Nene. Six years ago, she was 7 times as old as Nene. Find their present age. \n" ); document.write( "
Algebra.Com's Answer #284803 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Nene x years \n" ); document.write( "Liza 4x years \n" ); document.write( "... \n" ); document.write( "6 years ago \n" ); document.write( "Nene = x-6 \n" ); document.write( "Liza = 4x-6 \n" ); document.write( "... \n" ); document.write( "4x-6=7(x-6) \n" ); document.write( "4x-6=7x-42 \n" ); document.write( "7x-4x=42-6 \n" ); document.write( "3x=36 \n" ); document.write( "/3 \n" ); document.write( "x=12 Nene's age \n" ); document.write( ".. \n" ); document.write( "Liza = 4x = 48 years \n" ); document.write( " |