document.write( "Question 402685: Liza is four times as old as Nene. Six years ago, she was 7 times as old as Nene. Find their present age. \n" ); document.write( "
Algebra.Com's Answer #284803 by mananth(16946)\"\" \"About 
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Nene x years
\n" ); document.write( "Liza 4x years
\n" ); document.write( "...
\n" ); document.write( "6 years ago
\n" ); document.write( "Nene = x-6
\n" ); document.write( "Liza = 4x-6
\n" ); document.write( "...
\n" ); document.write( "4x-6=7(x-6)
\n" ); document.write( "4x-6=7x-42
\n" ); document.write( "7x-4x=42-6
\n" ); document.write( "3x=36
\n" ); document.write( "/3
\n" ); document.write( "x=12 Nene's age
\n" ); document.write( "..
\n" ); document.write( "Liza = 4x = 48 years
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