document.write( "Question 4083: In how many ways can a committee of 3 be selected from a group of 5? \n" ); document.write( "
Algebra.Com's Answer #2848 by CharStar(110)\"\" \"About 
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Since n=5 and r=3 (five people taken three at a time), then the equation is as follows\r
\n" ); document.write( "\n" ); document.write( "Use the following formula for combinations nCx=(n,x)=n!/x!(n-x)
\n" ); document.write( "Looks confusion doesn't it. \r
\n" ); document.write( "\n" ); document.write( "n=5
\n" ); document.write( "x=3\r
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\n" ); document.write( "\n" ); document.write( "Now solve\r
\n" ); document.write( "\n" ); document.write( "5 x 4 x 3 x 2 x 1
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\n" ); document.write( "3 x 2 x 1 x 2 x 1\r
\n" ); document.write( "\n" ); document.write( "You can cross out or multiply and divide. \r
\n" ); document.write( "\n" ); document.write( "120/12 = 10
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