document.write( "Question 402617: A given alloy contains 10% zinc and 20% copper. How many pounds of zinc and copper must be melted with 1000 pounds of the given alloy to produce another alloy analyzing 20% zinc and 24% copper? All percentages are by weight \n" ); document.write( "
Algebra.Com's Answer #284785 by robertb(5830)\"\" \"About 
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1.00z + 0.10*1000 + 0.00c = 0.20(z + 1000 + c)
\n" ); document.write( "<==> z + 100 = 0.20z + 200 + 0.20c
\n" ); document.write( "<==> 0.80z - 0.20c = 100 <---(A)
\n" ); document.write( "==> 4z - c = 500 ==> c = 4z - 500\r
\n" ); document.write( "\n" ); document.write( "Similarly
\n" ); document.write( "0.00z + 0.20*1000 + 1.00c = 0.24(z + 1000 + c)
\n" ); document.write( "<==> 200 + c = 0.24z + 240 + 0.24c
\n" ); document.write( "<==> -0.24z + 0.76c = 40 <---(B)
\n" ); document.write( "==> -0.24z + 0.76(4z - 500) = 40
\n" ); document.write( "==> -0.24z + 3.04z - 380 = 40
\n" ); document.write( "==> 2.8z = 420
\n" ); document.write( "==> z = 150 lbs zinc, and
\n" ); document.write( "==> c = 4*150 - 500 = 100 lbs copper.
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