document.write( "Question 402546: how many liters of 50% acid solution must be mixed with a 30% acid solution to get 180 liters of a 40% acid solution? \n" ); document.write( "
Algebra.Com's Answer #284767 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "50.00% ---------------- x \n" ); document.write( "30.00% ---------------- 180-x \n" ); document.write( "40.00% ---------------- 180\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50x+30( 180-x)= 40*180 \n" ); document.write( " \n" ); document.write( "50x+5400-30x=7200 \n" ); document.write( " \n" ); document.write( "20x=1800 \n" ); document.write( "/20 \n" ); document.write( " \n" ); document.write( "x=90 ml of 50% solution \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |