document.write( "Question 402443: A golf ball is launched upward with an initial speed of 30 m/sec by a golfer atop the Washington Monument, which is 160 m above the ground. How high above the ground will the ball be after 3 sec?\r
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Algebra.Com's Answer #284753 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Distance = rate*time only works for constant velocity problems. In this problem, we have the acceleration due to gravity.\r
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\n" ); document.write( "\n" ); document.write( "The formula for determining position given a constant acceleration is \"X+=+%281%2F2%29at%5E2+%2B+v%5B0%5Dt+%2B+x%5B0%5D\", where a = -9.81 m/s^2, \"v%5B0%5D\" is the original velocity, \"x%5B0%5D\" is the original position (this equation is derived using integral calculus). Here, t = 3 s, \"v%5B0%5D\" = 30 m/s, \"x%5B0%5D\" = 160 m. Therefore,\r
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\n" ); document.write( "\n" ); document.write( "\"X+=+%281%2F2%29%28-9.81m%2Fs%5E2%29%283s%29%5E2+%2B+%2830m%2Fs%29%283s%29+%2B+160m\" = 205.9 meters
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