document.write( "Question 402547: Hi!!!
\n" ); document.write( "Solve the system using substitution
\n" ); document.write( "y=8-x and 7=2-y
\n" ); document.write( "I got -13=x but I can't figure out what y equals.
\n" ); document.write( "Thank you so much!
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Algebra.Com's Answer #284714 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "1) \"y+=+8-x\" Substitute this for y in equation 2).
\n" ); document.write( "2) \"7+=+2-y\"
\n" ); document.write( "2a) \"7+=+2-%288-x%29\"
\n" ); document.write( "2b) \"7+=+2-8%2Bx\" Notice the change of sign on x.
\n" ); document.write( "2c) \"7+=+-6%2Bx\"
\n" ); document.write( "2d) \"13+=+x\" or \"x+=+13\" Notice that x is positive! Now substitute this value of x into either one of the two given equations and solve for y. Let's use equation 1).
\n" ); document.write( "1) \"y+=+8-x\" Substitute x = 13.
\n" ); document.write( "1a) \"y+=+8-13\" so \"y+=+-5\"
\n" ); document.write( "The solution is: (13,-5)
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