document.write( "Question 402458: How do I solve: 3p-2=-q
\n" ); document.write( "-q+2p=3 ?
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Algebra.Com's Answer #284683 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"3p-2=-q\" .........1\r
\n" ); document.write( "\n" ); document.write( "\"-q%2B2p=3+\" ..........2..solve this system by substitution
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\n" ); document.write( "\n" ); document.write( "\"3p-2=-q\" .........1..substitute \"-q\" in ...2...\r
\n" ); document.write( "\n" ); document.write( "\"3p-2%2B2p=3+\" ..........2..solve for \"p\"\r
\n" ); document.write( "\n" ); document.write( "\"5p+=+3%2B2+\"\r
\n" ); document.write( "\n" ); document.write( "\"5p+=+5+\"\r
\n" ); document.write( "\n" ); document.write( "\"p+=+5%2F5+\"\r
\n" ); document.write( "\n" ); document.write( "\"p+=+1+\"...now find \"q\"\r
\n" ); document.write( "\n" ); document.write( "\"3p-2=-q\" .........1\r
\n" ); document.write( "\n" ); document.write( "\"3%2A1-2=-q\" .........1\r
\n" ); document.write( "\n" ); document.write( "\"3-2=-q\" .........1\r
\n" ); document.write( "\n" ); document.write( "\"1=-q\" .........1..or, both sides multiply by \"-1\"\r
\n" ); document.write( "\n" ); document.write( " \"-1+=+q\"\r
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