document.write( "Question 402381: A rectangular parking lot has an area of 2400ft^2. If the width is 20 feet less than the length, what are the dimensions of the parking lot? \n" ); document.write( "
Algebra.Com's Answer #284680 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! A=LW \n" ); document.write( "W=L-20 \n" ); document.write( "2,400=L(L-20) \n" ); document.write( "2,400=L^2-20L \n" ); document.write( "L^2-20L-2,400=0 \n" ); document.write( "(L-60)(L+40)=0 \n" ); document.write( "L-60=0 \n" ); document.write( "L=60 ANS. FOR THE LENGTH. \n" ); document.write( "W=60-20=40 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "2,400=60*40 \n" ); document.write( "2,400=2,400 \n" ); document.write( " |