document.write( "Question 402381: A rectangular parking lot has an area of 2400ft^2. If the width is 20 feet less than the length, what are the dimensions of the parking lot? \n" ); document.write( "
Algebra.Com's Answer #284680 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
A=LW
\n" ); document.write( "W=L-20
\n" ); document.write( "2,400=L(L-20)
\n" ); document.write( "2,400=L^2-20L
\n" ); document.write( "L^2-20L-2,400=0
\n" ); document.write( "(L-60)(L+40)=0
\n" ); document.write( "L-60=0
\n" ); document.write( "L=60 ANS. FOR THE LENGTH.
\n" ); document.write( "W=60-20=40 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2,400=60*40
\n" ); document.write( "2,400=2,400
\n" ); document.write( "
\n" );