document.write( "Question 402382: Three consecutive even integers are such that the square of the first integer plus the square of the third integer is 136. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #284679 by checkley79(3341)\"\" \"About 
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Let x, x+2 & x=4 be the three integers.
\n" ); document.write( "x^2+(x+4)^2=136
\n" ); document.write( "x^2+x^2+8x+16=136
\n" ); document.write( "2x^2+8x+16-136=0
\n" ); document.write( "2x^2+8x-120=0
\n" ); document.write( "2(x^2+4x-60)=0
\n" ); document.write( "2(x-6)(x+10)=0
\n" ); document.write( "x-6=0
\n" ); document.write( "x=6 ans. for the smallest integer.
\n" ); document.write( "6+4=10 ans. for the largest integer.
\n" ); document.write( "Proof:
\n" ); document.write( "6^2+10^2=136
\n" ); document.write( "36+100=136
\n" ); document.write( "136=136
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