document.write( "Question 392130: Hello tutor,
\n" ); document.write( "This one question on my online homework assignment has been puzzling me for a while.\r
\n" ); document.write( "\n" ); document.write( "A circle is given centered at (0,0)with a radius of 2.\r
\n" ); document.write( "\n" ); document.write( "A line cuts through the center of the circle (slope of line unknown) but the line makes an angle of pi/3 with the x axis in the fourth quadrant.\r
\n" ); document.write( "\n" ); document.write( "This line continues and cuts through point Q (coordinates unknown) of the circle in the fourth quadrant.
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\n" ); document.write( "Another line forms a tangent to the circle at point Q and is perpendicular to the original line.\r
\n" ); document.write( "\n" ); document.write( "this second line ( which is tangent to the circle and perpendicular to the original line) continues and crosses the x axis at some point P (coordinates unknown)\r
\n" ); document.write( "\n" ); document.write( "* note that both lines share a point Q which lies on the circle.\r
\n" ); document.write( "\n" ); document.write( "We are asked to ultimately find the coordinates of point P (x , 0)\r
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\n" ); document.write( "there is an order of steps we have to perform.\r
\n" ); document.write( "\n" ); document.write( "a)Find the coordinates of the point Q (x,y)\r
\n" ); document.write( "\n" ); document.write( "b)Knowing two points on the original line, namely (0,0) and Q,compute the slope of the dotted line\r
\n" ); document.write( "\n" ); document.write( "c)Knowing the slope of the first line, Compute the slope of the second line (which is perpendicular to the first line)\r
\n" ); document.write( "\n" ); document.write( "d)We now know the point Q on the second line and the slope of the second line, so we find the equation of the line in the form
\n" ); document.write( "y=mx+b\r
\n" ); document.write( "\n" ); document.write( "e) therefor the coordinates of point P are (x,0) (Find x)
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Algebra.Com's Answer #284676 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
A circle is given centered at (0,0)with a radius of 2.
\n" ); document.write( "A line cuts through the center of the circle (slope of line unknown) but the line makes an angle of pi/3 with the x axis in the fourth quadrant.
\n" ); document.write( "This line continues and cuts through point Q (coordinates unknown) of the circle in the fourth quadrant.
\n" ); document.write( "------------------------------------------------------------------------------
\n" ); document.write( "Another line forms a tangent to the circle at point Q and is perpendicular to the original line.
\n" ); document.write( "this second line ( which is tangent to the circle and perpendicular to the original line) continues and crosses the x axis at some point P (coordinates unknown)
\n" ); document.write( "* note that both lines share a point Q which lies on the circle.
\n" ); document.write( "We are asked to ultimately find the coordinates of point P (x , 0)\r
\n" ); document.write( "\n" ); document.write( "..\r
\n" ); document.write( "\n" ); document.write( "According to the information given, I ended with a right triangle in quadrant IV, labeled as follows\"\r
\n" ); document.write( "\n" ); document.write( "O - center of circle
\n" ); document.write( "Q - point on circle where second line is tangent to circle and perpendicular to first line which goes thru origin.
\n" ); document.write( "P - point at which second line crosses x-axis\r
\n" ); document.write( "\n" ); document.write( "Angle at O - 60 deg
\n" ); document.write( "Angle at P - 30 deg
\n" ); document.write( "Angle at Q - 90 deg\r
\n" ); document.write( "\n" ); document.write( "Line segment OQ is equal to the radius = 2
\n" ); document.write( "since the reference angle of the first line is pi/3 = 60 deg, the angle at P must be 30 deg. This makes OP, the hypotenuse of the triangle twice that of OQ, being that OQ is opposite a 30 degree angle. Therefore the hypotenuse is = 4.\r
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\n" ); document.write( "\n" ); document.write( "ans: The coordinates at point P is (4,0)
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