document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402406>Question 402406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a boat travels 60 km upsteam in 5 hours. the boat travels the same direction downstream in 3 hours. what is the rate of the boat in still water? what is the rate of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284658 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=60*5=300 K. IS THE DISTANCE<BR>\n" );
document.write( "300/3=100 K/H IS THE SPEED ON THE RETURN TRIP.<BR>\n" );
document.write( "(100+60)/2=40/2=20 K/H IS THE DIFFERENCE IN (CURRENT SPEED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "100-20=80 K/H FOR THE BOAT<BR>\n" );
document.write( "60+20=80 DITTO </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );