document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402411>Question 402411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangular sign is 33 square meters. the base of the triangle is 1meter less than double the altitude. find the altitude and the base of the sign </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284647 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a triangular sign is 33 square meters. the base of the triangle is 1meter less than double the altitude. find the altitude and the base of the sign<BR>\n" );
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document.write( "Let a = altitude<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2a-1 = base<BR>\n" );
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document.write( "definition of area of any triangle:<BR>\n" );
document.write( "(1/2)*base*height<BR>\n" );
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document.write( "(1/2)(2a-1)(a) = 33<BR>\n" );
document.write( "(2a-1)(a) = 66<BR>\n" );
document.write( "2a^2-a = 66<BR>\n" );
document.write( "2a^2-a-66 = 0<BR>\n" );
document.write( "(2a-11)(a+6) = 0<BR>\n" );
document.write( "a = {11/2, -6}<BR>\n" );
document.write( "we can throw out the negative solution leaving<BR>\n" );
document.write( "a = 11/2 = 5.5 meters (altitude)<BR>\n" );
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document.write( "Base:<BR>\n" );
document.write( "2a-1 = 2(5.5)-1 = 11-1 = 10 meters <BR>\n" );
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