document.write( "Question 43460This question is from textbook 0-07-301602-0
\n" ); document.write( ": The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #28461 by aaaaaaaa(138)\"\" \"About 
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Let's represent the width as w. Therefore, the length is equal to\r
\n" ); document.write( "\n" ); document.write( "\"2w+%2B+2\"\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by 2w + 2l, and we can equate it to 52, by the problem statement:\r
\n" ); document.write( "\n" ); document.write( "\"2w+%2B+2%282w+%2B+2%29+=+52\"
\n" ); document.write( "Distributive property:
\n" ); document.write( "\"2w+%2B+4w+%2B+4+=+52\"
\n" ); document.write( "\"6w+%2B+4+=+52\"
\n" ); document.write( "\"6w+=+52+-+4\"
\n" ); document.write( "\"6w+=+48\"
\n" ); document.write( "\"w+=+48%2F6+=+8\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, if width is 8 cm, the length of our rectangle is \"2%2A8+%2B+2+=+16+%2B+2+=+18\" cm.
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