document.write( "Question 43460This question is from textbook 0-07-301602-0
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document.write( ": The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. \n" );
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Algebra.Com's Answer #28461 by aaaaaaaa(138)![]() ![]() ![]() You can put this solution on YOUR website! Let's represent the width as w. Therefore, the length is equal to\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by 2w + 2l, and we can equate it to 52, by the problem statement:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Distributive property: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, if width is 8 cm, the length of our rectangle is |