document.write( "Question 402215: What is the correct set up for this problem and how do I arrive at answer of a = -1/3.\r
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document.write( "5a + 1/4a + 6 = 3/4\r
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document.write( "I figured the LCD to be 2(2a + 3)\r
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document.write( "2(2a + 3)* 5a + 1/2(2a + 3) = 2(2a + 3)*3/4\r
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document.write( "= 5a + 1 = 2a + 3 * 3/2 (This is where I am having problem in solving this problem. \n" );
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Algebra.Com's Answer #284542 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! 5a + 1/(4a+6) = 3/4 \n" ); document.write( "5a + 1/(2(2a+3)) = 3/4 \n" ); document.write( "multiply both sides by 4(2a+3) \n" ); document.write( "5a(4(2a+3)) + 2 = 3(2a+3) \n" ); document.write( "5a(8a+12) + 2 = 3(2a+3) \n" ); document.write( "40a^2+60a + 2 = 6a+9 \n" ); document.write( "40a^2+54a + 2 = 9 \n" ); document.write( "40a^2+54a-7 = 0 \n" ); document.write( "apply the \"quadratic formula\" to get: \n" ); document.write( "a = {0.119, -1.469} \n" ); document.write( ". \n" ); document.write( "Details of quadratic: \n" ); document.write( "
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