document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402182>Question 402182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two complementary angles is 6 less than twice tthe other angle.Find the measure of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284541 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"One of two complementary angles is 6 less than twice tthe other angle.Find the measure of the angles.\"\r<BR>\n" );
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document.write( "x = one angle<BR>\n" );
document.write( "2x - 6 = other angle {six less than twice the other}\r<BR>\n" );
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document.write( "x + 2x - 6 = 90 {complimentary angles add up to 90 degrees}<BR>\n" );
document.write( "3x - 6 = 90 {combined like terms}<BR>\n" );
document.write( "3x = 96 {added 6 to both sides}<BR>\n" );
document.write( "x = 32 {divided both sides by 3}<BR>\n" );
document.write( "2x - 6 = 58 {substituted 32 for x, into 2x - 6}\r<BR>\n" );
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