document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401436>Question 401436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If $3000 is invested at 6% annual simple interest, how much should be invested at 9% annual simple interest so that the total yearly income from both investments is $585? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284534 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I=prt but you have two different amounts and percents so<BR>\n" );
document.write( "I=p1r1t1+p2r2t2   both t's are 1, since it's just 1 year<BR>\n" );
document.write( "585=3000*0.06*1+x*0.09*1<BR>\n" );
document.write( "585=180+0.09x subtract 180 from each side<BR>\n" );
document.write( "585-180=0.09x<BR>\n" );
document.write( "405=0.09x divide each side by 0.09<BR>\n" );
document.write( "4500=x<BR>\n" );
document.write( " </SPAN>\n" );
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