document.write( "Question 402199: Can someone please help me!!
\n" ); document.write( "√9x+67=x+5
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Algebra.Com's Answer #284517 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "If I m understanding Your question properly:
\n" ); document.write( "\"sqrt%289x+%2B+67%29+=+x%2B5\" |squaring both sides of the equation
\n" ); document.write( " 9x + 67 = (x + 5)(x+ 5)
\n" ); document.write( " 9x + 67 = x^2 + 10 + 25
\n" ); document.write( " x^2 + x - 42 = 0
\n" ); document.write( "factoring
\n" ); document.write( " (x + 7)(x - 6)=0 Note:SUM of the inner product(7x) and the outer product(-6x) =x
\n" ); document.write( " (x + 7)= 0 x = -7
\n" ); document.write( " (x - 6)=0 x = 6
\n" ); document.write( "CHECKING our Answer(s)***
\n" ); document.write( " \"sqrt%28+54%2B67%29+=+sqrt%28+121%29+=+11+=+6+%2B+5+\"
\n" ); document.write( " \"sqrt%28+-63%2B67%29+=+sqrt%28+4%29+=+2+=+-7+%2B+5+\" \n" ); document.write( "
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