document.write( "Question 402183: A chemist has a 30% saline solution and a 55% saline solution available. How many milliliters of each of these available solutions should she mix to obtain 700 ml of a 40% solution? \n" ); document.write( "
Algebra.Com's Answer #284515 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A chemist has a 30% saline solution and a 55% saline solution available. How many milliliters of each of these available solutions should she mix to obtain 700 ml of a 40% solution? \n" ); document.write( ". \n" ); document.write( "Let x = amount (ml) of 30% solution \n" ); document.write( "then \n" ); document.write( "700-x = amount (ml) of 55% solution \n" ); document.write( ". \n" ); document.write( ".30x + .55(700-x) = .40(700) \n" ); document.write( ".30x + 385 - .55x = 280 \n" ); document.write( "385 - .25x = 280 \n" ); document.write( "-.25x = -105 \n" ); document.write( "x = 420 ml (30% saline) \n" ); document.write( ". \n" ); document.write( "55% saline: \n" ); document.write( "700-x = 700-420 = 280 ml\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |