document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402141>Question 402141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)a solid rectangular block of copper 5cm by 4cm by 2cm is drawn out to make a cylindrical wire of diameter 2 mm. Calculate the length of wire.\r<BR>\n" );
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document.write( "2)water flows through a circular pipe of internal diameter 3cm at a speed of 10cm/s. If the pipe is full, how much water flows from one pipe in one minute ( answer in liters) \r<BR>\n" );
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document.write( "Show working out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284498 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume of copper = 4*5*2= 40cm^3<BR>\n" );
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document.write( "radius of wire =0.1 cm<BR>\n" );
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document.write( "Volume of wire = pi*r^2*l<BR>\n" );
document.write( "40 = pi*0.1^2*l<BR>\n" );
document.write( "40/(pi*0.1^2)= l<BR>\n" );
document.write( "length = 1273 cm\r<BR>\n" );
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document.write( "volume of pipe = pi*r^2*l<BR>\n" );
document.write( "V= pi*1.5^2*l0<BR>\n" );
document.write( "70.68 cm^3 /second<BR>\n" );
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document.write( "1cm^3= 0.001 liter<BR>\n" );
document.write( "70.68 cm^3= 0.07068 liters<BR>\n" );
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document.write( "This flow is per second<BR>\n" );
document.write( "for 60 second it will be 60 * 0.07068<BR>\n" );
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document.write( "the flow will be 4.24 liters /minute\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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