document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402069>Question 402069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alloys A and B are composed of metals X and Y in the ratios 5:3 and 6:7 respectively by weight. How many kg of X must be melted along with 20 kg of alloy A and 65 kg of alloy B so as to produce a new alloy containing 60% by weight of X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284489 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+20%2A%285%2F8%29+%2B+65%2A%286%2F13%29+=+%28x+%2B+20+%2B+65%29%2A0.60 ALIGN=MIDDLE  ALT=\"x+%2B+20%2A%285%2F8%29+%2B+65%2A%286%2F13%29+=+%28x+%2B+20+%2B+65%29%2A0.60\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "==> x + 12.5 + 30 = 0.60x + 12 + 39<BR>\n" );
document.write( "==> x + 42.5 = 0.60x + 51<BR>\n" );
document.write( "0.40x  = 8.5<BR>\n" );
document.write( "x = 21.25 kg of alloy X. </SPAN>\n" );
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