document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401817>Question 401817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I sketh the graph of this equation?<BR>\n" );
document.write( "x^2+y^2+4x-10y=21\r<BR>\n" );
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document.write( "I started of by doing this<BR>\n" );
document.write( "x^2+y^2+4x-10y=21<BR>\n" );
document.write( "x^2+4x+4+y^2-10y-25=21+4-25<BR>\n" );
document.write( "and got<BR>\n" );
document.write( "(x+2)^2+(y-5)^2=0<BR>\n" );
document.write( "by this I see that the center is (-2,5)<BR>\n" );
document.write( "and the radius is 0.\r<BR>\n" );
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document.write( "How would I sketch this and is what I did right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284484 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284484\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How would I sketh the graph of this equation?<BR>\n" );
document.write( "x^2+y^2+4x-10y=21<BR>\n" );
document.write( "I started of by doing this<BR>\n" );
document.write( "x^2+y^2+4x-10y=21<BR>\n" );
document.write( "x^2+4x+4+y^2-10y-25=21+4-25<BR>\n" );
document.write( "and got<BR>\n" );
document.write( "(x+2)^2+(y-5)^2=0<BR>\n" );
document.write( "by this I see that the center is (-2,5)<BR>\n" );
document.write( "and the radius is 0.<BR>\n" );
document.write( "How would I sketch this and is what I did right?<BR>\n" );
document.write( "..\r<BR>\n" );
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document.write( "You did everything right except when you completed the square for the y-term<BR>\n" );
document.write( "y^2-10y-25 this should have been y^2-10x+25. The third term is always a positive number because you are taking the square of a number. Your equation of the circle would now be (x+2)^2+(y-5)^2=50. You can now sketch the circle with center at (-2,5) and radius = sqrt(50) or 5sqrt(2)\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );