document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=402049>Question 402049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line containing the given point and perpendicular to the given line: (2,5); 2x+y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284453 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2,5); 2x+y=3<BR>\n" );
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document.write( "First, find slope of:<BR>\n" );
document.write( "2x+y=3<BR>\n" );
document.write( "y=-2x+3<BR>\n" );
document.write( "slope is -2<BR>\n" );
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document.write( "A line that is perpendicular must be the negative reciprocal:<BR>\n" );
document.write( "-2m = -1<BR>\n" );
document.write( "m = 1/2 (our new slope)<BR>\n" );
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document.write( "Plug our new slope and the given point (2,5) into the \"point-slope\" form:<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "y - 5 = (1/2)(x - 2)<BR>\n" );
document.write( "y - 5 = (1/2)x - 1<BR>\n" );
document.write( "y = (1/2)x + 4 (this is what they're looking for)\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );