document.write( "Question 397589: log(6*5^x-25*20^x)=x+log(25) \n" ); document.write( "
Algebra.Com's Answer #284376 by lwsshak3(11628) ![]() You can put this solution on YOUR website! log(6*5^x-25*20^x)=x+log(25) \n" ); document.write( ".. \n" ); document.write( "log(6*5^x-25*20^x)-log(25)=x \n" ); document.write( "=log{(6*5^x-25*20^x)/25}=x \n" ); document.write( "change to exponential form\r \n" ); document.write( "\n" ); document.write( "10^x={(6*5^x-25*20^x)/25} \n" ); document.write( "(2^x*5^x)=((6*5^x)-25(4^x*5^x))/25 \n" ); document.write( "divide by 5^x \n" ); document.write( "2^x=(6-25*4^x)/25 \n" ); document.write( "25*2^x=6-25*4^x \n" ); document.write( "25*4^x+25*2^x=6 \n" ); document.write( "25*4^x+25*2^x-6=0 \n" ); document.write( "4^x=2^2x \n" ); document.write( "let u=2^x \n" ); document.write( "then u^2=2^2x \n" ); document.write( "you then have a quadratic equation to solve \n" ); document.write( "25u^2+25u-6=0 \n" ); document.write( "(5u+6)(5u-1)=0 \n" ); document.write( "5u+6=0 \n" ); document.write( "u=-6/5 (reject, no solution} \n" ); document.write( "5u-1=0 \n" ); document.write( "u=1/5 \n" ); document.write( "u=2^x \n" ); document.write( "2^x=1/5=.2 \n" ); document.write( "xlog2=log(.2) \n" ); document.write( "x=(log(.2))/log2 \n" ); document.write( "from calculator \n" ); document.write( "ans: x=-2.322\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "Check: \n" ); document.write( "x+log25=-2.322+1.398=-.924 \n" ); document.write( "6*5^x=6*5^-2.322=.143 \n" ); document.write( "25*20^x=25*20^-2.322=.024 \n" ); document.write( "log(.143-.024)=log(.119)=-.924\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |