document.write( "Question 401820: 4x-2/3≥1/3 \n" ); document.write( "

Algebra.Com's Answer #284346 by checkley79(3341) $\"\"$ $\"About$

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4x-2/3≥1/3
\n" ); document.write( "4X>1/3+2/3
\n" ); document.write( "4X>=1
\n" ); document.write( "X>=1/4 OR .25 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "LET X=.26
\n" ); document.write( "4*.26-2/3>=1/3
\n" ); document.write( "1.04-2/3>=1/3
\n" ); document.write( "1.04>=1/3+2/3
\n" ); document.write( "1.04>=1 \n" ); document.write( "

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